"5th order mock theta functions"의 두 판 사이의 차이

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==articles==
 
==articles==
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* Nickolas Andersen, Vector-valued modular forms and the Mock Theta Conjectures, arXiv:1604.05294 [math.NT], April 18 2016, http://arxiv.org/abs/1604.05294
 
* G.E. Andrews, [http://www.jstor.org/stable/2000275 The fifth and seventh order mock theta functions]. Trans. Amer. Math. Soc. 293 (1986), pp. 113–134
 
* G.E. Andrews, [http://www.jstor.org/stable/2000275 The fifth and seventh order mock theta functions]. Trans. Amer. Math. Soc. 293 (1986), pp. 113–134
 
* <cite class="" id="CITEREFAndrews1988" style="line-height: 2em; font-style: normal;">Andrews, George E. (1988), "Ramanujan's fifth order mock theta functions as constant terms", <em style="line-height: 2em;">Ramanujan revisited (Urbana-Champaign, Ill., 1987)</em>,</cite>
 
* <cite class="" id="CITEREFAndrews1988" style="line-height: 2em; font-style: normal;">Andrews, George E. (1988), "Ramanujan's fifth order mock theta functions as constant terms", <em style="line-height: 2em;">Ramanujan revisited (Urbana-Champaign, Ill., 1987)</em>,</cite>

2016년 4월 19일 (화) 01:08 판

introduction

\[f_0(q) = \sum_{n\ge 0} {q^{n^2}\over (-q;q)_{n}}\] \[f_1(q) = \sum_{n\ge 0} {q^{n^2+n}\over (-q;q)_{n}}\] \[\phi_0(q) = \sum_{n\ge 0} {q^{n^2}(-q;q^2)_{n}}\] \[\phi_1(q) = \sum_{n\ge 0} {q^{(n+1)^2}(-q;q)_{n}}\] \[\psi_0(q) = \sum_{n\ge 0} {q^{(n+1)(n+2)/2}(-q;q)_{n}}\] \[\psi_1(q) = \sum_{n\ge 0} {q^{n(n+1)/2}(-q;q)_{n}}\] \[\chi_0(q) = \sum_{n\ge 0} {q^{n}\over (q^{n+1};q)_{n}} = 2F_0(q)-\phi_0(-q)\] \[\chi_1(q) = \sum_{n\ge 0} {q^{n}\over (q^{n+1};q)_{n+1}} = 2F_1(q)+q^{-1}\phi_1(-q)\] \[F_0(q) = \sum_{n\ge 0} {q^{2n^2}\over (q;q^2)_{n}}\] \[F_1(q) = \sum_{n\ge 0} {q^{2n^2+2n}\over (q;q^2)_{n+1}}\] \[\Psi_0(q) = -1 + \sum_{n \ge 0} { q^{5n^2}\over(1-q)(1-q^4)(1-q^6)(1-q^9)...(1-q^{5n+1})}\] \[\Psi_1(q) = -1 + \sum_{n \ge 0} { q^{5n^2}\over(1-q^2)(1-q^3)(1-q^7)(1-q^8)...(1-q^{5n+2}) }\]


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