"Light cone coordinates and gauge"의 두 판 사이의 차이

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==introduction==
  
 
*  light cone gague<br>
 
*  light cone gague<br>
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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">history==
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==history==
  
 
* http://www.google.com/search?hl=en&tbs=tl:1&q=
 
* http://www.google.com/search?hl=en&tbs=tl:1&q=
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==encyclopedia==
  
 
* http://en.wikipedia.org/wiki/Light_cone_gauge
 
* http://en.wikipedia.org/wiki/Light_cone_gauge
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==question and answers(Math Overflow)==
  
 
* http://mathoverflow.net/search?q=
 
* http://mathoverflow.net/search?q=
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*  구글 블로그 검색<br>
 
*  구글 블로그 검색<br>
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* http://arxiv.org/
 
* http://arxiv.org/
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* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier]
 
* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier]

2012년 10월 28일 (일) 17:39 판

introduction

  • light cone gague

 

1차원에서의 일반해

  • \(\frac{\partial^2 Y}{\partial t^2}=v^2\frac{\partial^2 Y}{\partial x^2}\) 또는 \(\mu\frac{\partial^2 Y}{\partial t^2}=T\frac{\partial^2 Y}{\partial x^2}\) (\(v=\sqrt{\frac{T}{\mu}}\))
  • 일반해는 \(Y=f(x+vt)+g(x-vt)\)로 주어진다
  • f는 왼쪽, g는 오른쪽으로 이동하는 파동이며, Y는 그 중첩으로 주어진다

 

(증명)

\(u=x+at\), \(v=x-at\)라 두자.

그러면 \(Y=f(u)+g(v)\)로 쓸 수 있다.

\(\frac{\partial Y}{\partial t}=\frac{\partial Y}{\partial u}\frac{\partial u}{\partial t} +\frac{\partial Y}{\partial v}\frac{\partial v}{\partial t}=f'(u)a+g'(v)(-a)=af'(u)-ag'(v)\)

 \(W(u,v)=\frac{\partial Y}{\partial t}=af'(u)-ag'(v)\).

\(\frac{\partial^2 Y}{\partial t^2}=\frac{\partial W}{\partial t}=\frac{\partial W}{\partial u}\frac{\partial u}{\partial t} +\frac{\partial W}{\partial v}\frac{\partial v}{\partial t}=af''(u)a-ag''(v)(-a)=a^2(f''(u)+g''(v))\)

 

 

\(\frac{\partial Y}{\partial x}=\frac{\partial Y}{\partial u}\frac{\partial u}{\partial x} +\frac{\partial Y}{\partial v}\frac{\partial v}{\partial x}=f'(u)+g'(v)\)

\(Z(u,v)=\frac{\partial Y}{\partial x}=f'(u)+g'(v)\)

\(\frac{\partial^2 Y}{\partial x^2}=\frac{\partial Z}{\partial x}=\frac{\partial Z}{\partial u}\frac{\partial u}{\partial x} +\frac{\partial Z}{\partial v}\frac{\partial v}{\partial x}=f''(u)+g''(v)\)

 

따라서

\(\frac{\partial^2 Y}{\partial t^2}=a^2\frac{\partial^2 Y}{\partial x^2}=a^2(f''(u)+g''(v))\)■

 

history

 

 

related items

 

 

encyclopedia

 

 

books

 

4909919

 

 

articles

 

 

 

question and answers(Math Overflow)

 

 

blogs

 

 

experts on the field

 

 

links