"Quantum dilogarithm"의 두 판 사이의 차이

2010년 5월 19일 (수) 06:28 판

\(\Phi(z)=\prod_{n=0}^{\infty}(1+zq^n)=\sum_{n\geq 0}\frac{q^{n(n-1)/2}}{(1-q)(1-q^2)\cdots(1-q^n)} z^n\)

\(\sum_{n=0}^{\infty}\frac{q^{\frac{A}{2}n^2+cn}}{(q)_n}\sim\exp(\frac{C}{t})\)

where C= sum of Rogers dilogarithms

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The hyperbolic volume of knots from quantum dilogarithm
- R. M. Kashaev, 1996
Remarks on the quantum dilogarithm
- V V Bazhanov and N Yu Reshetikhin, 1995 J. Phys. A: Math. Gen. 28 2217
Quantum Dilogarithm
- L.D.Fadeev and R.M.Kashaev, Mod. Phys. Lett. A. 9 (1994) p.427–434
http://ncatlab.org/nlab/show/quantum+dilogarithm

@@ 9번째 줄: / 9번째 줄: @@
 *  noncommutative geometry<br>
 * <math>uv=qvu</math><br>
+*  this is called the Weyl algebra<br>
@@ 14번째 줄: / 15번째 줄: @@
-<h5 style="margin: 0px; line-height: 2em;"> </h5>
+<h5 style="margin: 0px; line-height: 2em;">quantum dilogarithm</h5>
+<math>\Phi(z)=\prod_{n=0}^{\infty}(1+zq^n)=\sum_{n\geq 0}\frac{q^{n(n-1)/2}}{(1-q)(1-q^2)\cdots(1-q^n)} z^n</math>
-<math>\Phi(z)=\prod_{n=0}^{\infty}(1+zq^n)=\sum_{n\geq 0}\frac{q^{n(n-1)/2}}{(1-q)(1-q^2)\cdots(1-q^n)} z^n</math>