"Bailey pair and lemma"의 두 판 사이의 차이

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*   q-Pfaff-Sallschutz sum<br>
 
*   q-Pfaff-Sallschutz sum<br>
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<h5 style="line-height: 2em; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px;">Bailey pair</h5>
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<h5 style="MARGIN: 0px; LINE-HEIGHT: 2em;">Bailey pair</h5>
  
 
*  the sequence <math>\{\alpha_r\}, \{\beta_r\}</math> satisfying the following is called a Bailey pair<br><math>\beta_L=\sum_{r=0}^{L}\frac{\alpha_r}{(q)_{L-r}(aq)_{L+r}}</math><br>
 
*  the sequence <math>\{\alpha_r\}, \{\beta_r\}</math> satisfying the following is called a Bailey pair<br><math>\beta_L=\sum_{r=0}^{L}\frac{\alpha_r}{(q)_{L-r}(aq)_{L+r}}</math><br>
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<h5 style="line-height: 2em; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px;">Bailey chain</h5>
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<h5 style="MARGIN: 0px; LINE-HEIGHT: 2em;">Bailey chain</h5>
  
 
*  we derive a new Bailey chain from a known Bailey pair<br><math>\alpha^\prime_n= \frac{(\rho_1;q)_n(\rho_2;q)_n(aq/\rho_1\rho_2)^n}{(aq/\rho_1;q)_n(aq/\rho_2;q)_n}\alpha_n</math><br><math>\beta^\prime_n = \sum_{j\ge0}\frac{(\rho_1;q)_j(\rho_2;q)_j(aq/\rho_1\rho_2;q)_{n-j}(aq/\rho_1\rho_2)^j}{(q;q)_{n-j}(aq/\rho_1;q)_n(aq/\rho_2;q)_n}\beta_j</math><br>
 
*  we derive a new Bailey chain from a known Bailey pair<br><math>\alpha^\prime_n= \frac{(\rho_1;q)_n(\rho_2;q)_n(aq/\rho_1\rho_2)^n}{(aq/\rho_1;q)_n(aq/\rho_2;q)_n}\alpha_n</math><br><math>\beta^\prime_n = \sum_{j\ge0}\frac{(\rho_1;q)_j(\rho_2;q)_j(aq/\rho_1\rho_2;q)_{n-j}(aq/\rho_1\rho_2)^j}{(q;q)_{n-j}(aq/\rho_1;q)_n(aq/\rho_2;q)_n}\beta_j</math><br>
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* http://www.google.com/search?hl=en&tbs=tl:1&q=
 
* http://www.google.com/search?hl=en&tbs=tl:1&q=
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* [[Bloch group]]<br>
 
* [[Bloch group]]<br>
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*   <br>
 
*   <br>
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* [[2010년 books and articles]]<br>
 
* [[2010년 books and articles]]<br>
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* [http://arxiv.org/abs/0910.2062v2 50 Years of Bailey's lemma]<br>
 
* [http://arxiv.org/abs/0910.2062v2 50 Years of Bailey's lemma]<br>
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* [http://dx.doi.org/10.1142/S0217751X97001110 Virasoro character identities from the Andrews–Bailey construction]<br>
 
* [http://dx.doi.org/10.1142/S0217751X97001110 Virasoro character identities from the Andrews–Bailey construction]<br>
 
**  Foda, O., Quano, Y.-H, Int. J. Mod. Phys. A 12, 1651–1675 (1997)<br>
 
**  Foda, O., Quano, Y.-H, Int. J. Mod. Phys. A 12, 1651–1675 (1997)<br>
*  <br>[http://matwbn.icm.edu.pl/ksiazki/aa/aa43/aa4326.pdf Special values of the dilogarithm function]<br>
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* [http://matwbn.icm.edu.pl/ksiazki/aa/aa43/aa4326.pdf Special values of the dilogarithm function]<br>
 
** J. H. Loxton, 1984
 
** J. H. Loxton, 1984
 
* [http://dx.doi.org/10.1112%2Fjlms%2Fs1-37.1.504 Wilfrid Norman Bailey]<br>
 
* [http://dx.doi.org/10.1112%2Fjlms%2Fs1-37.1.504 Wilfrid Norman Bailey]<br>
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* http://mathoverflow.net/search?q=
 
* http://mathoverflow.net/search?q=
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*  구글 블로그 검색<br>
 
*  구글 블로그 검색<br>
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* http://arxiv.org/
 
* http://arxiv.org/
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* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier]
 
* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier]

2010년 6월 18일 (금) 15:07 판

introduction
  •  q-Pfaff-Sallschutz sum

 

 

Bailey lemma

 

 

 

Bailey pair
  • the sequence \(\{\alpha_r\}, \{\beta_r\}\) satisfying the following is called a Bailey pair
    \(\beta_L=\sum_{r=0}^{L}\frac{\alpha_r}{(q)_{L-r}(aq)_{L+r}}\)
  • conjugate Bailey pair  \(\{\delta_r\}, \{\gamma_r\}\)
    \(\gamma_L=\sum_{r=L}^{\infty}\frac{\delta_r}{(q)_{r-L}(aq)_{r+L}}\)

 

 

Bailey chain
  • we derive a new Bailey chain from a known Bailey pair
    \(\alpha^\prime_n= \frac{(\rho_1;q)_n(\rho_2;q)_n(aq/\rho_1\rho_2)^n}{(aq/\rho_1;q)_n(aq/\rho_2;q)_n}\alpha_n\)
    \(\beta^\prime_n = \sum_{j\ge0}\frac{(\rho_1;q)_j(\rho_2;q)_j(aq/\rho_1\rho_2;q)_{n-j}(aq/\rho_1\rho_2)^j}{(q;q)_{n-j}(aq/\rho_1;q)_n(aq/\rho_2;q)_n}\beta_j\)
  • corollary. by taking  \(\rho_1,\rho_2\to \infty\) , we get 
     
    \(\alpha^\prime_n= a^nq^{n^2}\alpha_n\)
    \(\beta^\prime_n = \sum_{r=0}^{L}\frac{a^rq^{r^2}}{(q)_{L-r}}\beta_j\)

 

 

history

 

 

 

related items

 

 

encyclopedia

 

 

books

[[4909919|]]

 

 

articles

 

 

question and answers(Math Overflow)

 

 

blogs

 

 

experts on the field

 

 

links