"Lebesgue identity"의 두 판 사이의 차이
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+ | * '''[Alladi&Gordon1993] 278&279p'''<br> | ||
+ | * Lebesgue's identity<br><math>\sum_{k\geq 0}\frac{q^{k(k+1)/2}(-zq)_{k}}{(q)_{k}}=(-zq^2;q^2)_{\infty}(-q)_{\infty}=\prod_{m=1}^{\infty} (1+zq^{2m})(1+q^{m})</math><br> | ||
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+ | <h5 style="line-height: 2em; margin: 0px;">a 2x2 matrix</h5> | ||
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+ | * Use q-binomial identity<br> <math>(-z;q)_{n}= \sum_{r=0}^{n} \begin{bmatrix} n\\ r\end{bmatrix}_{q}q^{r(r-1)/2}z^r</math> and <math>(-zq;q)_{k}= \sum_{r=0}^{k} \begin{bmatrix} k\\ r\end{bmatrix}_{q}q^{r(r+1)/2}z^r</math><br> | ||
+ | * we get a rank 2 form of the Lebesgue's identity<br><math>\sum_{k\geq 0}\frac{q^{k(k+1)/2}(-zq)_{k}}{(q)_{k}}=\sum_{i,j\geq 0}\frac{z^{j}q^{(i+j)(i+j+1)/2+j(j+1)/2}}{(q)_{i}(q)_{j}}=(-zq^2;q^2)_{\infty}(-q)_{\infty}</math> where <math>i=k-j</math>.<br> | ||
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+ | * here we get a 2x2 matrix<br><math> \begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}</math><br> | ||
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+ | <h5 style="line-height: 2em; margin: 0px;">specializations</h5> | ||
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+ | * From the above, we can derive<br><math>\sum_{i,j\geq 0}\frac{q^{(i^2+2ij+2j^2)/2+i/2}}{(q)_{i}(q)_{j}}=(-q;q^2)_{\infty}(-q)_{\infty}</math><br> | ||
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+ | * http://www.google.com/search?hl=en&tbs=tl:1&q= | ||
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+ | <h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">related items</h5> | ||
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+ | * http://en.wikipedia.org/wiki/ | ||
+ | * http://www.scholarpedia.org/ | ||
+ | * http://www.proofwiki.org/wiki/ | ||
+ | * Princeton companion to mathematics([[2910610/attachments/2250873|Companion_to_Mathematics.pdf]]) | ||
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+ | * [[2010년 books and articles]]<br> | ||
+ | * http://gigapedia.info/1/ | ||
+ | * http://gigapedia.info/1/ | ||
+ | * http://www.amazon.com/s/ref=nb_ss_gw?url=search-alias%3Dstripbooks&field-keywords= | ||
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+ | [[4909919|]] | ||
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+ | * '''[Alladi&Gordon1993]'''[http://dx.doi.org/10.1016/0097-3165%2893%2990061-C Partition identities and a continued fraction of Ramanujan]<br> | ||
+ | ** Krishnaswami Alladi and Basil Gordon, 1993 | ||
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+ | * http://www.ams.org/mathscinet | ||
+ | * [http://www.zentralblatt-math.org/zmath/en/ ]http://www.zentralblatt-math.org/zmath/en/ | ||
+ | * http://arxiv.org/ | ||
+ | * http://www.pdf-search.org/ | ||
+ | * http://pythagoras0.springnote.com/ | ||
+ | * [http://math.berkeley.edu/%7Ereb/papers/index.html http://math.berkeley.edu/~reb/papers/index.html] | ||
+ | * http://dx.doi.org/ | ||
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+ | * http://mathoverflow.net/search?q= | ||
+ | * http://mathoverflow.net/search?q= | ||
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+ | * 구글 블로그 검색<br> | ||
+ | ** http://blogsearch.google.com/blogsearch?q= | ||
+ | ** http://blogsearch.google.com/blogsearch?q= | ||
+ | * http://ncatlab.org/nlab/show/HomePage | ||
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+ | <h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">experts on the field</h5> | ||
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+ | * http://arxiv.org/ | ||
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+ | <h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">links</h5> | ||
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+ | * [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier] | ||
+ | * [http://pythagoras0.springnote.com/pages/1947378 수식표현 안내] | ||
+ | * [http://www.research.att.com/%7Enjas/sequences/index.html The On-Line Encyclopedia of Integer Sequences] | ||
+ | * http://functions.wolfram.com/ | ||
+ | * |
2010년 9월 25일 (토) 22:42 판
introduction
- [Alladi&Gordon1993] 278&279p
- Lebesgue's identity
\(\sum_{k\geq 0}\frac{q^{k(k+1)/2}(-zq)_{k}}{(q)_{k}}=(-zq^2;q^2)_{\infty}(-q)_{\infty}=\prod_{m=1}^{\infty} (1+zq^{2m})(1+q^{m})\)
a 2x2 matrix
- Use q-binomial identity
\((-z;q)_{n}= \sum_{r=0}^{n} \begin{bmatrix} n\\ r\end{bmatrix}_{q}q^{r(r-1)/2}z^r\) and \((-zq;q)_{k}= \sum_{r=0}^{k} \begin{bmatrix} k\\ r\end{bmatrix}_{q}q^{r(r+1)/2}z^r\) - we get a rank 2 form of the Lebesgue's identity
\(\sum_{k\geq 0}\frac{q^{k(k+1)/2}(-zq)_{k}}{(q)_{k}}=\sum_{i,j\geq 0}\frac{z^{j}q^{(i+j)(i+j+1)/2+j(j+1)/2}}{(q)_{i}(q)_{j}}=(-zq^2;q^2)_{\infty}(-q)_{\infty}\) where \(i=k-j\).
- here we get a 2x2 matrix
\( \begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}\)
specializations
- From the above, we can derive
\(\sum_{i,j\geq 0}\frac{q^{(i^2+2ij+2j^2)/2+i/2}}{(q)_{i}(q)_{j}}=(-q;q^2)_{\infty}(-q)_{\infty}\)
history
encyclopedia
- http://en.wikipedia.org/wiki/
- http://www.scholarpedia.org/
- http://www.proofwiki.org/wiki/
- Princeton companion to mathematics(Companion_to_Mathematics.pdf)
books
- 2010년 books and articles
- http://gigapedia.info/1/
- http://gigapedia.info/1/
- http://www.amazon.com/s/ref=nb_ss_gw?url=search-alias%3Dstripbooks&field-keywords=
[[4909919|]]
articles
- [Alladi&Gordon1993]Partition identities and a continued fraction of Ramanujan
- Krishnaswami Alladi and Basil Gordon, 1993
- http://www.ams.org/mathscinet
- [1]http://www.zentralblatt-math.org/zmath/en/
- http://arxiv.org/
- http://www.pdf-search.org/
- http://pythagoras0.springnote.com/
- http://math.berkeley.edu/~reb/papers/index.html
- http://dx.doi.org/
question and answers(Math Overflow)
blogs
- 구글 블로그 검색
- http://ncatlab.org/nlab/show/HomePage
experts on the field