"Lagrangian formulation of electromagetism"의 두 판 사이의 차이
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imported>Pythagoras0 |
imported>Pythagoras0 |
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* Lagrangian for a charged particle in an electromagnetic field <math>L=T-V</math> | * Lagrangian for a charged particle in an electromagnetic field <math>L=T-V</math> | ||
:<math>L(q,\dot{q})=m||\dot{q}||-e\phi+eA_{i}\dot{q}^{i}</math> | :<math>L(q,\dot{q})=m||\dot{q}||-e\phi+eA_{i}\dot{q}^{i}</math> | ||
| − | |||
| − | |||
* Euler-Lagrange equations | * Euler-Lagrange equations | ||
:<math>p_{i}=\frac{\partial{L}}{\partial{\dot{q}^{i}}}=m\frac{\dot{q}_{i}}{||\dot{q}_{i}||}+eA_{i}=mv_{i}+eA_{i}</math> | :<math>p_{i}=\frac{\partial{L}}{\partial{\dot{q}^{i}}}=m\frac{\dot{q}_{i}}{||\dot{q}_{i}||}+eA_{i}=mv_{i}+eA_{i}</math> | ||
| 15번째 줄: | 13번째 줄: | ||
==Lagrangian for electromagnetic tensor== | ==Lagrangian for electromagnetic tensor== | ||
| + | ===free=== | ||
* 상호작용이 없는 전자기장의 라그랑지안은 다음과 같다 | * 상호작용이 없는 전자기장의 라그랑지안은 다음과 같다 | ||
$$\mathcal{L}_{\text{EM}}= - \frac{1}{4}F_{\mu\nu}F^{\mu\nu}=\frac{1}{2}(\mathbf{E}^2-\mathbf{B}^2)$$ | $$\mathcal{L}_{\text{EM}}= - \frac{1}{4}F_{\mu\nu}F^{\mu\nu}=\frac{1}{2}(\mathbf{E}^2-\mathbf{B}^2)$$ | ||
이 때 <math>F_{\mu\nu} = \partial_\mu A_\nu - \partial_\nu A_\mu \,\!</math>는 전자기텐서, $A=(A_{\mu})$는 전자기 포텐셜 | 이 때 <math>F_{\mu\nu} = \partial_\mu A_\nu - \partial_\nu A_\mu \,\!</math>는 전자기텐서, $A=(A_{\mu})$는 전자기 포텐셜 | ||
| + | * action | ||
| + | :<math>S=-\frac{1}{4}\int F^{\alpha\beta}F_{\alpha\beta}\,d^{4}x</math> | ||
* 라그랑지안은 전자기 포텐셜의 다음과 같은 변환에 대하여 불변이다 | * 라그랑지안은 전자기 포텐셜의 다음과 같은 변환에 대하여 불변이다 | ||
:<math>A_{\mu}(x) \to A_{\mu}(x)-\partial_{\mu}\Lambda(x)</math> | :<math>A_{\mu}(x) \to A_{\mu}(x)-\partial_{\mu}\Lambda(x)</math> | ||
| 26번째 줄: | 27번째 줄: | ||
$$ | $$ | ||
* see http://www.damtp.cam.ac.uk/user/tong/qft/six.pdf | * see http://www.damtp.cam.ac.uk/user/tong/qft/six.pdf | ||
| + | |||
| + | ===in the presence of $j$ and $\rho$=== | ||
| + | * action | ||
| + | $$S[\phi,A]=\int_{t_1}^{t_2}\int_{\mathbb{R}^3}-\rho\phi+j\cdot A+\frac{\epsilon_0}{2}E^2-\frac{1}{2\mu_0}B^2\,dV\,dt$$ | ||
| + | * w.r.t $\phi$ | ||
| + | $$\nabla\cdot E=\frac{\rho}{\epsilon_0}$$ | ||
| + | * w.r.t $A$ | ||
| + | $$\nabla\times B=\mu_0j+\epsilon_0\mu_0\frac{\partial E}{\partial t}$$ | ||
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| 42번째 줄: | 53번째 줄: | ||
* [http://www.physics.sfsu.edu/~lea/courses/grad/fldlagr.PDF The field Lagrangian] | * [http://www.physics.sfsu.edu/~lea/courses/grad/fldlagr.PDF The field Lagrangian] | ||
* http://www.lecture-notes.co.uk/susskind/classical-mechanics/lecture-8/the-electromagnetic-lagrangian/ | * http://www.lecture-notes.co.uk/susskind/classical-mechanics/lecture-8/the-electromagnetic-lagrangian/ | ||
| − | * http://unapologetic.wordpress.com/2012/07/16/the-higgs-mechanism-part-1-lagrangians/ | + | |
| + | |||
| + | ==blogs== | ||
| + | * Higgs mechanism | ||
| + | ** http://unapologetic.wordpress.com/2012/07/16/the-higgs-mechanism-part-1-lagrangians/ | ||
| + | ** http://unapologetic.wordpress.com/2012/07/17/the-higgs-mechanism-part-2-examples-of-lagrangian-field-equations/ | ||
| + | ** http://unapologetic.wordpress.com/2012/07/18/the-higgs-mechanism-part-3-gauge-symmetries/ | ||
| + | ** http://unapologetic.wordpress.com/2012/07/19/the-higgs-mechanism-part-4-symmetry-breaking/ | ||
| + | |||
==questions== | ==questions== | ||
* http://physics.stackexchange.com/questions/3005/derivation-of-maxwells-equations-from-field-tensor-lagrangian?rq=1 | * http://physics.stackexchange.com/questions/3005/derivation-of-maxwells-equations-from-field-tensor-lagrangian?rq=1 | ||
2013년 3월 24일 (일) 16:39 판
Lagrangian for a particle
- Lagrangian for a charged particle in an electromagnetic field \(L=T-V\)
\[L(q,\dot{q})=m||\dot{q}||-e\phi+eA_{i}\dot{q}^{i}\]
- Euler-Lagrange equations
\[p_{i}=\frac{\partial{L}}{\partial{\dot{q}^{i}}}=m\frac{\dot{q}_{i}}{||\dot{q}_{i}||}+eA_{i}=mv_{i}+eA_{i}\] $$ F_{i}=\frac{\partial{L}}{\partial{q^{i}}}=\frac{\partial}{\partial{{q}^{i}}}(eA_{j}\dot{q}^{j})=e\frac{\partial{A_{j}}}{\partial{q}^{i}}\dot{q}^{j} $$
- equation of motion\(\dot{p}=F\) Therefore we get
\[m\frac{dv_{i}}{dt}=eF_{ij}\dot{q}^{j}\]. This is what we call the Lorentz force law.
- force on a particle is same as \(e\mathbf{E}+e\mathbf{v}\times \mathbf{B}\)
Lagrangian for electromagnetic tensor
free
- 상호작용이 없는 전자기장의 라그랑지안은 다음과 같다
$$\mathcal{L}_{\text{EM}}= - \frac{1}{4}F_{\mu\nu}F^{\mu\nu}=\frac{1}{2}(\mathbf{E}^2-\mathbf{B}^2)$$ 이 때 \(F_{\mu\nu} = \partial_\mu A_\nu - \partial_\nu A_\mu \,\!\)는 전자기텐서, $A=(A_{\mu})$는 전자기 포텐셜
- action
\[S=-\frac{1}{4}\int F^{\alpha\beta}F_{\alpha\beta}\,d^{4}x\]
- 라그랑지안은 전자기 포텐셜의 다음과 같은 변환에 대하여 불변이다
\[A_{\mu}(x) \to A_{\mu}(x)-\partial_{\mu}\Lambda(x)\] 여기서 $\Lambda(x)$는 임의의 스칼라장
- equation of motion
$$ 0 = \partial_\mu F^{\mu\nu} $$
in the presence of $j$ and $\rho$
- action
$$S[\phi,A]=\int_{t_1}^{t_2}\int_{\mathbb{R}^3}-\rho\phi+j\cdot A+\frac{\epsilon_0}{2}E^2-\frac{1}{2\mu_0}B^2\,dV\,dt$$
- w.r.t $\phi$
$$\nabla\cdot E=\frac{\rho}{\epsilon_0}$$
- w.r.t $A$
$$\nabla\times B=\mu_0j+\epsilon_0\mu_0\frac{\partial E}{\partial t}$$
memo
expositions
- THOMAS YU LAGRANGIAN FORMULATION OF THE ELECTROMAGNETIC FIELD
- The field Lagrangian
- http://www.lecture-notes.co.uk/susskind/classical-mechanics/lecture-8/the-electromagnetic-lagrangian/
blogs
- Higgs mechanism
- http://unapologetic.wordpress.com/2012/07/16/the-higgs-mechanism-part-1-lagrangians/
- http://unapologetic.wordpress.com/2012/07/17/the-higgs-mechanism-part-2-examples-of-lagrangian-field-equations/
- http://unapologetic.wordpress.com/2012/07/18/the-higgs-mechanism-part-3-gauge-symmetries/
- http://unapologetic.wordpress.com/2012/07/19/the-higgs-mechanism-part-4-symmetry-breaking/