"Finite dimensional representations of Sl(2)"의 두 판 사이의 차이

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<h5>character formula</h5>
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<h5 style="line-height: 2em; margin: 0px;">specialization</h5>
  
Weyl-Kac formula<br><math>ch(V)={\sum_{w\in W} (-1)^{\ell(w)}w(e^{\lambda+\rho}) \over e^{\rho}\prod_{\alpha>0}(1-e^{-\alpha})}</math><br>
+
Cartan matrix<br><math>\mathbf{A} = \begin{pmatrix} 2 \end{pmatrix}</math><br>
for trivial representation, we get denominator identity<br><math>{\sum_{w\in W} (-1)^{\ell(w)}w(e^{\rho}) = e^{\rho}\prod_{\alpha>0}(1-e^{-\alpha})^{m_{\alpha}}}</math><br>
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root system<br><math>\Phi=\{\alpha,-\alpha\}</math><br>
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* <br><br>
  
 
 
 
 
17번째 줄: 18번째 줄:
 
 
 
 
  
<h5 style="line-height: 2em; margin: 0px;">specialization</h5>
+
<h5 style="line-height: 2em; margin: 0px;">representation theory</h5>
  
*  Cartan matrix<br><math>\mathbf{A} = \begin{pmatrix} 2 \end{pmatrix}</math><br>
+
 
*  root system<br><math>\Phi=\{\alpha,-\alpha\}</math><br>
 
  
 
*  integrable weights and Weyl vector<br><math>\omega=\frac{1}{2}\alpha</math><br><math>\rho=\omega</math><br> integrable weights <math>\lambda=n\omega</math><br>
 
*  integrable weights and Weyl vector<br><math>\omega=\frac{1}{2}\alpha</math><br><math>\rho=\omega</math><br> integrable weights <math>\lambda=n\omega</math><br>
 
*  Weyl-Kac formula<br><math>\operatorname{ch}L(n\omega)=\frac{e^{(n+1)\omega}-e^{-(n+1)\omega}}{e^{\omega}-e^{-\omega}}=e^{n\omega}+e^{(n-2)\omega}+\cdots+e^{-n\omega}</math><br>
 
*  Weyl-Kac formula<br><math>\operatorname{ch}L(n\omega)=\frac{e^{(n+1)\omega}-e^{-(n+1)\omega}}{e^{\omega}-e^{-\omega}}=e^{n\omega}+e^{(n-2)\omega}+\cdots+e^{-n\omega}</math><br>
 <br>
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 +
there is a unique k+1 dimensional irreducible module <math>V_k</math><br>
  
 
 
 
 
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<h5 style="line-height: 2em; margin: 0px;">Chebyshev polynomial of the 2nd kind</h5>
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 +
 
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<h5 style="line-height: 3.428em; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic', dotum, gulim, sans-serif; font-size: 1.166em; background-image: ; background-color: initial; background-position: 0px 100%;">character formula and Chebyshev polynomial of the 2nd kind</h5>
 +
 
 +
*  Weyl-Kac formula<br><math>ch(V)={\sum_{w\in W} (-1)^{\ell(w)}w(e^{\lambda+\rho}) \over e^{\rho}\prod_{\alpha>0}(1-e^{-\alpha})}</math><br>
 +
*  for trivial representation, we get denominator identity<br><math>{\sum_{w\in W} (-1)^{\ell(w)}w(e^{\rho}) = e^{\rho}\prod_{\alpha>0}(1-e^{-\alpha})^{m_{\alpha}}}</math><br>
  
 
* <math>U_{n+1}(x) & = 2xU_n(x) - U_{n-1}(x)</math><br> U_0[x]=1<br> U_1[x]=2 x<br> U_2[x]=-1+4 x^2<br> U_3[x]=-4 x+8 x^3<br>
 
* <math>U_{n+1}(x) & = 2xU_n(x) - U_{n-1}(x)</math><br> U_0[x]=1<br> U_1[x]=2 x<br> U_2[x]=-1+4 x^2<br> U_3[x]=-4 x+8 x^3<br>
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* '''[GW1998]'''
 
* '''[GW1998]'''
 
* dimension of symmetric algebra and exterior algebra of V_k
 
* dimension of symmetric algebra and exterior algebra of V_k
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 +
 
  
 
 
 
 
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<math>\prod_{j=0}^{k}(1-tq^{k-2j})^{-1}=\sum_{m_0,\cdots,m_k}t^{m_0+\cdots+m_k}q^{(k-0)m_0+(k-2)m_1+\cdots+(2-k)m_{k-1}+(0-k)m_k}</math>
 
<math>\prod_{j=0}^{k}(1-tq^{k-2j})^{-1}=\sum_{m_0,\cdots,m_k}t^{m_0+\cdots+m_k}q^{(k-0)m_0+(k-2)m_1+\cdots+(2-k)m_{k-1}+(0-k)m_k}</math>
 
 
 
  
 
Now we can easily check
 
Now we can easily check
93번째 줄: 99번째 줄:
  
 
<h5 style="line-height: 3.428em; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic', dotum, gulim, sans-serif; font-size: 1.166em; background-image: ; background-color: initial; background-position: 0px 100%;">exterior algebra of sl(2) representations</h5>
 
<h5 style="line-height: 3.428em; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic', dotum, gulim, sans-serif; font-size: 1.166em; background-image: ; background-color: initial; background-position: 0px 100%;">exterior algebra of sl(2) representations</h5>
 
 
 
 
 
 
  
 
*  q-binomial type formula<br><math>\prod_{j=0}^{k}(1+tq^{k-2j})}=\sum_{j=0}^{k+1}\begin{bmatrix} k+1 \\ j\end{bmatrix}_{q}q^{j(j-1)/2}t^j</math><br>
 
*  q-binomial type formula<br><math>\prod_{j=0}^{k}(1+tq^{k-2j})}=\sum_{j=0}^{k+1}\begin{bmatrix} k+1 \\ j\end{bmatrix}_{q}q^{j(j-1)/2}t^j</math><br>
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<h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103);">encyclopedia</h5>
 
<h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103);">encyclopedia</h5>
  
 +
* [http://pythagoras0.springnote.com/pages/4783755 q-이항정리]
 
* [http://pythagoras0.springnote.com/pages/4682477 체비셰프 다항식]
 
* [http://pythagoras0.springnote.com/pages/4682477 체비셰프 다항식]
 
* http://en.wikipedia.org/wiki/
 
* http://en.wikipedia.org/wiki/

2010년 4월 10일 (토) 15:47 판

introduction

 

 

specialization
  • Cartan matrix
    \(\mathbf{A} = \begin{pmatrix} 2 \end{pmatrix}\)
  • root system
    \(\Phi=\{\alpha,-\alpha\}\)


 

 

representation theory

 

  • integrable weights and Weyl vector
    \(\omega=\frac{1}{2}\alpha\)
    \(\rho=\omega\)
    integrable weights \(\lambda=n\omega\)
  • Weyl-Kac formula
    \(\operatorname{ch}L(n\omega)=\frac{e^{(n+1)\omega}-e^{-(n+1)\omega}}{e^{\omega}-e^{-\omega}}=e^{n\omega}+e^{(n-2)\omega}+\cdots+e^{-n\omega}\)
  • there is a unique k+1 dimensional irreducible module \(V_k\)

 

 

 

character formula and Chebyshev polynomial of the 2nd kind
  • Weyl-Kac formula
    \(ch(V)={\sum_{w\in W} (-1)^{\ell(w)}w(e^{\lambda+\rho}) \over e^{\rho}\prod_{\alpha>0}(1-e^{-\alpha})}\)
  • for trivial representation, we get denominator identity
    \({\sum_{w\in W} (-1)^{\ell(w)}w(e^{\rho}) = e^{\rho}\prod_{\alpha>0}(1-e^{-\alpha})^{m_{\alpha}}}\)
  • \(U_{n+1}(x) & = 2xU_n(x) - U_{n-1}(x)\)
    U_0[x]=1
    U_1[x]=2 x
    U_2[x]=-1+4 x^2
    U_3[x]=-4 x+8 x^3
  • character evaluated at an element of SU(2) with the eigenvalues e^{i\theta}, e^{-i\theta} is given by the Chebyshev polynomials
    \(U_n(\cos\theta)= \frac{\sin (n+1)\theta}{\sin \theta}\)
  • \(w=e^{i\theta}\), \(z=w+w^{-1}=2\cos\theta\)
    \(p_i(z)=\frac{w^{i+1}-w^{-i-1}}{w-w^{-1}}\)
    \(p_{0}(z)=1\)
    \(p_{1}(z)=z\)
    \(p_{2}(z)=z^2-1\)
    \(p_{3}(z)=z^3-2z\)
    \(p_i(z)^2=1+p_{i-1}(z)p_{i+1}(z)\)

 

 

Hermite reciprocity
  • [GW1998]
  • dimension of symmetric algebra and exterior algebra of V_k

 

 

symmetric power of sl(2) representations
  • q-binomial type formula
    \(\prod_{j=0}^{k}(1-tq^{k-2j})^{-1}=\sum_{j=0}^{\infty}t^j\begin{bmatrix} k+j\\ k\end{bmatrix}_{q}\)
  •  
    the character of j-th symmetric power of V_k is
    \(\begin{bmatrix} k+j\\ k\end{bmatrix}_{q}\)
    where the q-analogue of the natural number is defined as 
    \([n]_{q}=\frac{q^n-q^{-n}}{q-q^{-1}}\)

 

(proof)

Fix a k throughout the argument.

Let \(F_j(q)\) be the character of j-th symmetric power of V_k.

\(F_j(q)=\sum_{m_0,\cdots,m_k}q^{(k-0)m_0+(k-2)m_1+\cdots+(2-k)m_{k-1}+(0-k)m_k}\)

where \(m_0+m_1+\cdots+m_k=j\)

Now consider the generating function

\(F(t,q)=\sum_{j=0}^{\infty}F_j(q)t^j\)

I claim that

\(F(t,q)=\sum_{j=0}^{\infty}F_j(q)t^j=\prod_{j=0}^{k}(1-tq^{k-2j})^{-1}\). 

To prove that see the power series expansion of a factor\[(1-tq^{k-2j})^{-1}=\sum_{m=0}^{\infty}t^mq^{m(k-2j)}\]. Therefore

\(\prod_{j=0}^{k}(1-tq^{k-2j})^{-1}=\sum_{m_0,\cdots,m_k}t^{m_0+\cdots+m_k}q^{(k-0)m_0+(k-2)m_1+\cdots+(2-k)m_{k-1}+(0-k)m_k}\)

Now we can easily check

\(\prod_{j=0}^{k}(1-tq^{k-2j})^{-1}=\sum_{j=0}^{\infty}t^j\begin{bmatrix} k+j\\ k\end{bmatrix}_{q}\)

 

 

 

exterior algebra of sl(2) representations
  • q-binomial type formula
    \(\prod_{j=0}^{k}(1+tq^{k-2j})}=\sum_{j=0}^{k+1}\begin{bmatrix} k+1 \\ j\end{bmatrix}_{q}q^{j(j-1)/2}t^j\)
  • the character of j-th exterior algebra of V_k is
    \(\begin{bmatrix} k+1 \\ j\end{bmatrix}_{q}q^{j(j-1)/2}\)

 

 

Catalan numbers
  1. f[n_] := Integrate[(2 Cos[Pi*x])^n*2 (Sin[Pi*x])^2, {x, 0, 1}]
    Table[Simplify[f[2 k]], {k, 1, 10}]
    Table[CatalanNumber[n], {n, 1, 10}]

 

 

 

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[[2010년 books and articles|]]

 

 

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