"Quantum modular forms"의 두 판 사이의 차이

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imported>Pythagoras0
imported>Pythagoras0
13번째 줄: 13번째 줄:
 
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===special case===
 
===special case===
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* If $b=2$ and  $a=1$, then $\zeta_{b}^{a}=-1$
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* $U(-1;\zeta)$ becomes a finite sum if $\zeta$ is a root of unity
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$$
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U(-1;\zeta)=\sum_{n=0}^{k-1} (1+\zeta)^2(1+\zeta^2)^2\cdots (1+\zeta^n)^2\zeta^{n+1}
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$$
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* $R(-1;q)=f(q)$ and $C(-1;q)=b(q)$ in [[3rd order mock theta functions]]
 
* $R(-1;q)=f(q)$ and $C(-1;q)=b(q)$ in [[3rd order mock theta functions]]
* $b=2$, $a=1$,
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==related items==
 
==related items==
 
* [[quantum dilogarithm]]
 
* [[quantum dilogarithm]]
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==computational resource==
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* https://docs.google.com/file/d/0B8XXo8Tve1cxWmFPWkZTMVdBeDA/edit
  
  
 
[[분류:Mock modular forms]]
 
[[분류:Mock modular forms]]

2013년 3월 18일 (월) 14:50 판

example

  • unimodular generating function

$$ U(w;q)=\sum_{n=0}^{\infty}(wq;q)_{n}(w^{-1}q;q)_{n}q^{n+1} $$

$$R(w;q)=\sum_{n=0}^\infty \frac{q^{n^2}}{(wq;q)_n(w^{-1}q;q)_n}$$

$$C(w;q)=\frac{(q)_{\infty}}{(wq;q)_{\infty}(w^{-1}q;q)_{\infty}}$$

  • limit formula $\zeta_b=e^{2\pi i/b}$, $1\le a <b$, for every root of unity $\zeta$, there exists an integer $c$ such that

$$ \lim_{q\to \zeta} R(\zeta_{b}^{a};q)-\zeta_{b^2}^{c} C(\zeta_{b}^{a};q)=-(1-\zeta_{b}^{a})(1-\zeta_{b}^{-a})U(\zeta_{b}^{a};\zeta) $$

special case

  • If $b=2$ and $a=1$, then $\zeta_{b}^{a}=-1$
  • $U(-1;\zeta)$ becomes a finite sum if $\zeta$ is a root of unity

$$ U(-1;\zeta)=\sum_{n=0}^{k-1} (1+\zeta)^2(1+\zeta^2)^2\cdots (1+\zeta^n)^2\zeta^{n+1} $$



related items


computational resource