"Delta potential scattering"의 두 판 사이의 차이

수학노트
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:<math>T=|t|^2=1-R=\cfrac{1}{1+\cfrac{m^2\lambda^2}{\hbar^4k^2}}= \cfrac{1}{1+\cfrac{m \lambda^2}{2\hbar^2 E}}\,\!</math>
 
:<math>T=|t|^2=1-R=\cfrac{1}{1+\cfrac{m^2\lambda^2}{\hbar^4k^2}}= \cfrac{1}{1+\cfrac{m \lambda^2}{2\hbar^2 E}}\,\!</math>
  
 
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==계산 리소스==
 
==계산 리소스==
 
* https://docs.google.com/file/d/0B8XXo8Tve1cxZjdDY3BfRFEwM0E/edit
 
* https://docs.google.com/file/d/0B8XXo8Tve1cxZjdDY3BfRFEwM0E/edit
  
 
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==encyclopedia==
 
==encyclopedia==
47번째 줄: 47번째 줄:
 
* [http://en.wikipedia.org/wiki/Delta_potential_barrier_%28QM%29 http://en.wikipedia.org/wiki/Delta_potential_barrier_(QM)]
 
* [http://en.wikipedia.org/wiki/Delta_potential_barrier_%28QM%29 http://en.wikipedia.org/wiki/Delta_potential_barrier_(QM)]
 
[[분류:physics]]
 
[[분류:physics]]
[[분류:math and physics]]
 
 
[[분류:math and physics]]
 
[[분류:math and physics]]
 
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==메타데이터==
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===위키데이터===
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* ID :  [https://www.wikidata.org/wiki/Q2381860 Q2381860]
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===Spacy 패턴 목록===
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* [{'LOWER': 'delta'}, {'LEMMA': 'potential'}]

2021년 2월 17일 (수) 02:30 기준 최신판

introduction

  • Let the potential is given by

\[V(x) = \lambda\delta(x)\]

  • wave function

\[\psi(x) = \begin{cases} \psi_{\mathrm L}(x) = A_{\mathrm r}e^{ikx} + A_{\mathrm l}e^{-ikx}, & \text{ if } x<0; \\ \psi_{\mathrm R}(x) = B_{\mathrm r}e^{ikx} + B_{\mathrm l}e^{-ikx}, & \text{ if } x>0, \end{cases}\]

  • we impose two conditions on the wave function
    • the wave function be continuous in the origin
    • integrate the Schrödinger equation around x = 0, over an interval [−ε, +ε] and In the limit as ε → 0, the right-hand side of this equation vanishes; the left-hand side becomes
  • first condition

\[\psi(0) =\psi_L(0) = \psi_R(0) = A_r + A_l = B_r + B_l\] \[A_r + A_l - B_r - B_l = 0\]

  • second condition

\[ -\frac{\hbar^2}{2 m} \int_{-\epsilon}^{+\epsilon} \psi''(x) \,dx + \int_{-\epsilon}^{+\epsilon} V(x)\psi(x) \,dx = E \int_{-\epsilon}^{+\epsilon} \psi(x) \,dx\]

  • LHS becomes \(-\frac{\hbar^2}{2m}[\psi_R'(0)-\psi_L'(0)] +\lambda\psi(0)\)
  • RHS becomes 0

\[-A_r + A_l + B_r - B_l =\frac{2m\lambda}{ik\hbar^2}(A_r + A_l)\]

  • the coefficients \(A_r, A_l,B_r,B_l\) must satisfy

\[ \begin{cases} A_r + A_l - B_r - B_l = 0 \\ -A_r + A_l + B_r - B_l =\frac{2m\lambda}{ik\hbar^2}(A_r + A_l) \end{cases} \]

delta potential scattering

  • special case of scattering problem \(A_r=1, A_l=r, B_r=t , B_l = 0\)
  • wave function

\[\psi(x) = \begin{cases} \psi_{\mathrm L}(x) = e^{ikx} + re^{-ikx}, & \text{ if } x<0; \\ \psi_{\mathrm R}(x) =te^{ikx} , & \text{ if } x>0, \end{cases}\]

  • \(t-r=1\)

\[t=\cfrac{1}{1-\cfrac{m\lambda}{i\hbar^2k}}\,\!\] \[r=\cfrac{1}{\cfrac{i\hbar^2 k}{m\lambda} - 1}\,\!\] \[R=|r|^2=\cfrac{1}{1+\cfrac{\hbar^4k^2}{m^2\lambda^2}}= \cfrac{1}{1+\cfrac{2\hbar^2 E}{m\lambda^2}}.\,\!\] \[T=|t|^2=1-R=\cfrac{1}{1+\cfrac{m^2\lambda^2}{\hbar^4k^2}}= \cfrac{1}{1+\cfrac{m \lambda^2}{2\hbar^2 E}}\,\!\]


계산 리소스


encyclopedia

메타데이터

위키데이터

Spacy 패턴 목록

  • [{'LOWER': 'delta'}, {'LEMMA': 'potential'}]