"Quasipolynomial"의 두 판 사이의 차이

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imported>Pythagoras0
 
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==example==
 
==example==
* assume $a_n = \left((-1)^n+1\right)+\left((-1)^n+3\right) n$
+
* assume <math>a_n = \left((-1)^n+1\right)+\left((-1)^n+3\right) n</math>
 
* then
 
* then
$$
+
:<math>
 
\sum_{n=0}^{\infty}a_nt^n = \frac{2 \left(t^3+3 t^2+t+1\right)}{(1-t)^2 (t+1)^2}
 
\sum_{n=0}^{\infty}a_nt^n = \frac{2 \left(t^3+3 t^2+t+1\right)}{(1-t)^2 (t+1)^2}
$$
+
</math>
  
  
 
==some results==
 
==some results==
 
;thm (Ehrhart's theorem for rational polytopes)
 
;thm (Ehrhart's theorem for rational polytopes)
If $P$ is a rational convex $d$-polytope, then $L_{P}(t)$ is a quasipolynomial in $t$ of degree $d$. Its period divides the least common multiple of the denominator of the coordinates of the vertices of $P$.
+
If <math>P</math> is a rational convex <math>d</math>-polytope, then <math>L_{P}(t)</math> is a quasipolynomial in <math>t</math> of degree <math>d</math>. Its period divides the least common multiple of the denominator of the coordinates of the vertices of <math>P</math>.
  
 
;lemma (Beck-Robins ex. 3.19)
 
;lemma (Beck-Robins ex. 3.19)
If $\sum_{t \ge 0} f(t)z^t = \frac{g(z)}{h(z)}$, then $f$ is a quasipolynomial of degree $d$ with period $p$ if and only if $g$ and $h$ are polynomials such that $\deg(g)<\deg(h)$, all roots of $h$ are $p$-th roots of unity of multiplicity at most $d+1$, and there is a root of multiplicity equal to $d+1$ (all of this assuming that $g/h$ has been reduced to lowest terms.
+
If <math>\sum_{t \ge 0} f(t)z^t = \frac{g(z)}{h(z)}</math>, then <math>f</math> is a quasipolynomial of degree <math>d</math> with period <math>p</math> if and only if <math>g</math> and <math>h</math> are polynomials such that <math>\deg(g)<\deg(h)</math>, all roots of <math>h</math> are <math>p</math>-th roots of unity of multiplicity at most <math>d+1</math>, and there is a root of multiplicity equal to <math>d+1</math> (all of this assuming that <math>g/h</math> has been reduced to lowest terms.
  
  
 
;thm (Beck-Robins ex. 3.25)
 
;thm (Beck-Robins ex. 3.25)
Suppose $P$ is a rational $d$-polytope with denominator $p$. Then
+
Suppose <math>P</math> is a rational <math>d</math>-polytope with denominator <math>p</math>. Then
$$
+
:<math>
 
\operatorname{Ehr}_{P}(z) = \frac{f(z)}{(1-z^p)^{d+1}}
 
\operatorname{Ehr}_{P}(z) = \frac{f(z)}{(1-z^p)^{d+1}}
$$
+
</math>
where $f$ is a polynomial with nonnegative integral coefficients.
+
where <math>f</math> is a polynomial with nonnegative integral coefficients.
  
  
 
;prop (?)
 
;prop (?)
Let $f$ be a quasipolynomial of degree $d$. If $f(n+1)\geq f(n)$ for all $n\in \mathbb{N}$, then the top degree coefficient of $f$ must be constant.
+
Let <math>f</math> be a quasipolynomial of degree <math>d</math>. If <math>f(n+1)\geq f(n)</math> for all <math>n\in \mathbb{N}</math>, then the top degree coefficient of <math>f</math> must be constant.
 
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2020년 11월 16일 (월) 04:25 기준 최신판

example

  • assume \(a_n = \left((-1)^n+1\right)+\left((-1)^n+3\right) n\)
  • then

\[ \sum_{n=0}^{\infty}a_nt^n = \frac{2 \left(t^3+3 t^2+t+1\right)}{(1-t)^2 (t+1)^2} \]


some results

thm (Ehrhart's theorem for rational polytopes)

If \(P\) is a rational convex \(d\)-polytope, then \(L_{P}(t)\) is a quasipolynomial in \(t\) of degree \(d\). Its period divides the least common multiple of the denominator of the coordinates of the vertices of \(P\).

lemma (Beck-Robins ex. 3.19)

If \(\sum_{t \ge 0} f(t)z^t = \frac{g(z)}{h(z)}\), then \(f\) is a quasipolynomial of degree \(d\) with period \(p\) if and only if \(g\) and \(h\) are polynomials such that \(\deg(g)<\deg(h)\), all roots of \(h\) are \(p\)-th roots of unity of multiplicity at most \(d+1\), and there is a root of multiplicity equal to \(d+1\) (all of this assuming that \(g/h\) has been reduced to lowest terms.


thm (Beck-Robins ex. 3.25)

Suppose \(P\) is a rational \(d\)-polytope with denominator \(p\). Then \[ \operatorname{Ehr}_{P}(z) = \frac{f(z)}{(1-z^p)^{d+1}} \] where \(f\) is a polynomial with nonnegative integral coefficients.


prop (?)

Let \(f\) be a quasipolynomial of degree \(d\). If \(f(n+1)\geq f(n)\) for all \(n\in \mathbb{N}\), then the top degree coefficient of \(f\) must be constant.