"가우스-요르단 소거법"의 두 판 사이의 차이
Pythagoras0 (토론 | 기여) |
Pythagoras0 (토론 | 기여) |
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(같은 사용자의 중간 판 3개는 보이지 않습니다) | |||
4번째 줄: | 4번째 줄: | ||
* 선형연립방정식의 해법, 역행렬의 계산 등에 활용할 수 있다 | * 선형연립방정식의 해법, 역행렬의 계산 등에 활용할 수 있다 | ||
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==예== | ==예== | ||
12번째 줄: | 12번째 줄: | ||
<math>\left( \begin{array}{ccc} 1 & -3 & 0 \\ -1 & 1 & 5 \\ 0 & 1 & 1 \end{array} \right)</math> 에 가우스-조단 소거법을 적용한 경우 | <math>\left( \begin{array}{ccc} 1 & -3 & 0 \\ -1 & 1 & 5 \\ 0 & 1 & 1 \end{array} \right)</math> 에 가우스-조단 소거법을 적용한 경우 | ||
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<math>\begin{array}{l} \left( \begin{array}{ccc} 1 & -3 & 0 \\ -1 & 1 & 5 \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & -3 & 0 \\ 0 & -2 & 5 \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & -3 & 0 \\ 0 & 1 & -\frac{5}{2} \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & \frac{7}{2} \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right) \end{array}</math> | <math>\begin{array}{l} \left( \begin{array}{ccc} 1 & -3 & 0 \\ -1 & 1 & 5 \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & -3 & 0 \\ 0 & -2 & 5 \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & -3 & 0 \\ 0 & 1 & -\frac{5}{2} \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & \frac{7}{2} \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right) \end{array}</math> | ||
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==메모== | ==메모== | ||
58번째 줄: | 58번째 줄: | ||
<references /> | <references /> | ||
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[[분류:선형대수학]] | [[분류:선형대수학]] | ||
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+ | ==메타데이터== | ||
+ | ===위키데이터=== | ||
+ | * ID : [https://www.wikidata.org/wiki/Q1195020 Q1195020] | ||
+ | ===Spacy 패턴 목록=== | ||
+ | * [{'LOWER': 'gauss'}, {'OP': '*'}, {'LOWER': 'jordan'}, {'LEMMA': 'elimination'}] |
2021년 2월 17일 (수) 03:56 기준 최신판
개요
- 선형대수학의 중요한 알고리즘의 하나
- 선형연립방정식의 해법, 역행렬의 계산 등에 활용할 수 있다
예
\(\left( \begin{array}{ccc} 1 & -3 & 0 \\ -1 & 1 & 5 \\ 0 & 1 & 1 \end{array} \right)\) 에 가우스-조단 소거법을 적용한 경우
\(\begin{array}{l} \left( \begin{array}{ccc} 1 & -3 & 0 \\ -1 & 1 & 5 \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & -3 & 0 \\ 0 & -2 & 5 \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & -3 & 0 \\ 0 & 1 & -\frac{5}{2} \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 1 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & \frac{7}{2} \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & -\frac{15}{2} \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & -\frac{5}{2} \\ 0 & 0 & 1 \end{array} \right) \\ \left( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right) \end{array}\)
메모
관련된 항목들
매스매티카 파일 및 계산 리소스
노트
위키데이터
- ID : Q1195020
말뭉치
- Here you can solve systems of simultaneous linear equations using Gauss-Jordan Elimination Calculator with complex numbers online for free with a very detailed solution.[1]
- In fact Gauss-Jordan elimination algorithm is divided into forward elimination and back substitution.[1]
- But practically it is more convenient to eliminate all elements below and above at once when using Gauss-Jordan elimination calculator.[1]
- To understand Gauss-Jordan elimination algorithm better input any example, choose "very detailed solution" option and examine the solution.[1]
- Gauss-Jordan Elimination is an algorithm that can be used to solve systems of linear equations and to find the inverse of any invertible matrix.[2]
- It's called Gauss-Jordan elimination, to find the inverse of the matrix.[3]
- And we did this using Gauss-Jordan elimination.[3]
- To obtain an initial basic feasible solution, the Gauss-Jordan elimination procedure can be used to convert the Ax = b in the canonical form.[4]
- Using row operations to convert a matrix into reduced row echelon form is sometimes called Gauss–Jordan elimination.[5]
- A variant of Gaussian elimination called Gauss–Jordan elimination can be used for finding the inverse of a matrix, if it exists.[5]
- To convert any matrix to its reduced row echelon form, Gauss-Jordan elimination is performed.[6]
- Gauss-Jordan elimination is a mechanical procedure for transforming a given system of linear equations to \(Rx = d\) with \(R\) in RREF using only elementary row operations.[7]
- This more-complete method of solving is called "Gauss-Jordan elimination" (with the equations ending up in what is called "reduced-row-echelon form").[8]
- Gauss–Jordan elimination is backward stable for matrices diagonally dominant by rows and not for those diagonally dominant by columns.[9]
- Use Gauss-Jordan elimination on augmented matrices to solve a linear system and calculate the matrix inverse.[10]
- We apply the Gauss-Jordan Elimination method: we obtain the reduced row echelon form from the augmented matrix of the equation system by performing elemental operations in rows (or columns).[11]
- But in case of Gauss-Jordan Elimination Method, we only have to form a reduced row echelon form (diagonal matrix).[12]
- Gauss-Jordan Elimination Method can be used for finding the solution of a systems of linear equations which is applied throughout the mathematics.[12]
- The Gauss-Jordan Elimination method can be used in determining the inverse of a square matrix.[12]
소스
- ↑ 1.0 1.1 1.2 1.3 Gauss-Jordan Elimination Calculator
- ↑ M.7 Gauss-Jordan Elimination
- ↑ 3.0 3.1 Inverting a 3x3 matrix using Gaussian elimination (video)
- ↑ Gauss-Jordan Elimination - an overview
- ↑ 5.0 5.1 Gaussian elimination
- ↑ Brilliant Math & Science Wiki
- ↑ Gauss-Jordan Elimination
- ↑ Systems of Linear Equations: Gaussian Elimination
- ↑ A Note on the Stability of Gauss–Jordan Elimination for Diagonally Dominant Matrices
- ↑ Reduced row echelon form (Gauss-Jordan elimination)
- ↑ GAUSSIAN ELIMINATION: SOLVNG LINEAR EQUATION SYSTEMS: EXAMPLES AND SOLVED PROBLEMS: HIGH SCHOOL
- ↑ 12.0 12.1 12.2 Program for Gauss-Jordan Elimination Method
메타데이터
위키데이터
- ID : Q1195020
Spacy 패턴 목록
- [{'LOWER': 'gauss'}, {'OP': '*'}, {'LOWER': 'jordan'}, {'LEMMA': 'elimination'}]