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Pythagoras0 (토론 | 기여) |
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| (사용자 2명의 중간 판 14개는 보이지 않습니다) | |||
| 1번째 줄: | 1번째 줄: | ||
| − | + | ==개요== | |
| − | + | ||
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| − | + | ||
| − | + | ==예== | |
| − | <math> | + | <math>v_{1}=(1, 0)</math> |
| − | + | <math>v_{2}=(-\sqrt{3}/2, 1/2)</math> | |
| − | < | + | :<math> |
| + | \begin{array}{|rcl|} | ||
| + | \hline | ||
| + | (1,0) & = & v_1 \\ | ||
| + | \hline | ||
| + | \left(\frac{\sqrt{3}}{2},\frac{1}{2}\right) & = & \sqrt{3} v_1+v_2 \\ | ||
| + | \hline | ||
| + | \left(\frac{1}{2},\frac{\sqrt{3}}{2}\right) & = & 2 v_1+\sqrt{3} v_2 \\ | ||
| + | \hline | ||
| + | (0,1) & = & \sqrt{3} v_1+2 v_2 \\ | ||
| + | \hline | ||
| + | \left(-\frac{1}{2},\frac{\sqrt{3}}{2}\right) & = & v_1+\sqrt{3} v_2 \\ | ||
| + | \hline | ||
| + | \left(-\frac{\sqrt{3}}{2},\frac{1}{2}\right) & = & v_2 \\ | ||
| + | \hline | ||
| + | (-1,0) & = & -v_1 \\ | ||
| + | \hline | ||
| + | \left(-\frac{\sqrt{3}}{2},-\frac{1}{2}\right) & = & -\sqrt{3} v_1-v_2 \\ | ||
| + | \hline | ||
| + | \left(-\frac{1}{2},-\frac{\sqrt{3}}{2}\right) & = & -2 v_1-\sqrt{3} v_2 \\ | ||
| + | \hline | ||
| + | (0,-1) & = & -\sqrt{3} v_1-2 v_2 \\ | ||
| + | \hline | ||
| + | \left(\frac{1}{2},-\frac{\sqrt{3}}{2}\right) & = & -v_1-\sqrt{3} v_2 \\ | ||
| + | \hline | ||
| + | \left(\frac{\sqrt{3}}{2},-\frac{1}{2}\right) & = & -v_2 \\ | ||
| + | \hline | ||
| + | \end{array} | ||
| + | </math> | ||
| − | + | ==역사== | |
| + | |||
| + | |||
* http://www.google.com/search?hl=en&tbs=tl:1&q= | * http://www.google.com/search?hl=en&tbs=tl:1&q= | ||
| − | * [[ | + | * [[수학사 연표]] |
| − | + | ||
| − | + | ||
| − | + | ==메모== | |
| − | + | ||
* Math Overflow http://mathoverflow.net/search?q= | * Math Overflow http://mathoverflow.net/search?q= | ||
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| − | + | ==관련된 항목들== | |
| + | * [[행렬과 선형사상]] | ||
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| − | + | ==매스매티카 파일 및 계산 리소스== | |
| − | * | + | * https://docs.google.com/file/d/0B8XXo8Tve1cxZi1vYlpSZTVoRjQ/edit |
| − | + | [[분류:선형대수학]] | |
| − | |||
2020년 11월 12일 (목) 01:53 기준 최신판
개요
예
\(v_{1}=(1, 0)\)
\(v_{2}=(-\sqrt{3}/2, 1/2)\)
\[ \begin{array}{|rcl|} \hline (1,0) & = & v_1 \\ \hline \left(\frac{\sqrt{3}}{2},\frac{1}{2}\right) & = & \sqrt{3} v_1+v_2 \\ \hline \left(\frac{1}{2},\frac{\sqrt{3}}{2}\right) & = & 2 v_1+\sqrt{3} v_2 \\ \hline (0,1) & = & \sqrt{3} v_1+2 v_2 \\ \hline \left(-\frac{1}{2},\frac{\sqrt{3}}{2}\right) & = & v_1+\sqrt{3} v_2 \\ \hline \left(-\frac{\sqrt{3}}{2},\frac{1}{2}\right) & = & v_2 \\ \hline (-1,0) & = & -v_1 \\ \hline \left(-\frac{\sqrt{3}}{2},-\frac{1}{2}\right) & = & -\sqrt{3} v_1-v_2 \\ \hline \left(-\frac{1}{2},-\frac{\sqrt{3}}{2}\right) & = & -2 v_1-\sqrt{3} v_2 \\ \hline (0,-1) & = & -\sqrt{3} v_1-2 v_2 \\ \hline \left(\frac{1}{2},-\frac{\sqrt{3}}{2}\right) & = & -v_1-\sqrt{3} v_2 \\ \hline \left(\frac{\sqrt{3}}{2},-\frac{1}{2}\right) & = & -v_2 \\ \hline \end{array} \]
역사
메모
- Math Overflow http://mathoverflow.net/search?q=
관련된 항목들