"Symmetry and conserved quantitiy : Noether's theorem"의 두 판 사이의 차이

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<h5>introduction</h5>
 
<h5>introduction</h5>
  
<math>j^{\mu)(x)= \frac{\partial \mathcal{L}}{\partial ( \partial_\mu \phi )}\left(\frac{\partial\alpha_{s}(\phi)}{\partial s} \right) </math>
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*  current <br><math>j(x)=(j^0(x),j^1(x),j^2(x),j^3(x))</math><br><math>j^{\mu}(x)= \frac{\partial \mathcal{L}}{\partial ( \partial_\mu \phi )}\left(\frac{\partial\alpha_{s}(\phi)}{\partial s} \right) </math><br>
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*  obeys the continuity equation<br><math>\partial_{\mu} J^{\mu}=\sum_{\mu=0}^{3}\frac{\partial j^{\mu}}{\partial x^{\mu}}=0</math><br>
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*   <br>  <br>
  
 
 
 
 

2011년 10월 2일 (일) 06:06 판

introduction
  • current 
    \(j(x)=(j^0(x),j^1(x),j^2(x),j^3(x))\)
    \(j^{\mu}(x)= \frac{\partial \mathcal{L}}{\partial ( \partial_\mu \phi )}\left(\frac{\partial\alpha_{s}(\phi)}{\partial s} \right) \)

 

  • obeys the continuity equation
    \(\partial_{\mu} J^{\mu}=\sum_{\mu=0}^{3}\frac{\partial j^{\mu}}{\partial x^{\mu}}=0\)
  •  
     

 

 

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