"Electromagnetics"의 두 판 사이의 차이

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<h5>notations</h5>
 
 
* charge density <math>{\rho} </math> (for point charge, density will be a Dirac delta function)
 
  
 
 
 
 
 
<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">electromagnetic field (four vector potential)</h5>
 
 
* [http://pythagoras0.springnote.com/pages/12166408 포벡터 포텐셜과 맥스웰 방정식]
 
*  in covariant formulation, this is a '''1-form'''<br><math>A=A_{0}dx^{0}+A_{1}dx^{1}+A_{2}dx^{2}+A_{3}dx^{3}</math><br>  <br>
 
  
 
 
 
 
  
<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">conserved four-current</h5>
 
 
* this is necessary for Maxwell equations with sources
 
* describes the distribution and motion of charged particles
 
* charge density <math>{\rho} </math> (for point charge, density will be a Dirac delta function)
 
* current density <math>\mathbf{J}=(J_x,J_y,J_z)</math>
 
*  charge density and current density<br><math>J^a = \left(c \rho, \mathbf{J} \right)</math><br>
 
*  four vector is called a conserved current if <math>\partial_{a}J^{a}=0</math><br>
 
*  in covariant formulation, this is a '''3-form'''<br><math>J=\rho dx\wedge dy \wedge dz - J_{z}dx\wedge dy \wedge dt -J_{x}dy\wedge dz\wedge dt-J_{y}dz\wedge dx\wedge dt</math><br>
 
 
 
 
 
 
 
 
<h5>covariant formulation using differential form</h5>
 
 
*  electromagnetic field strength<br><math>F_{\mu\nu} = \partial_\mu A_\nu - \partial_\nu A_\mu \,\!</math><br>
 
*  In [[Gauge theory]], we regard F as 2-form, A as 1-form<br>
 
* <math>A=A_{0}dx^{0}+A_{1}dx^{1}+A_{2}dx^{2}+A_{3}dx^{3}</math><br>
 
* <math>F=F_{01}dx^{0}\wedge dx^{1}+F_{02}dx^{0}\wedge dx^{2}+\cdots</math><br>
 
* <math>J=(-\rho,J_1,J_2,J_3)</math><br>
 
*  Maxwell's equation can be recast into<br>
 
** <math>dF=0</math> (<math>\nabla \cdot \mathbf{B} = 0</math>, <math>\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}} {\partial t}</math>)<br>
 
** <math>d*F=J</math> (<math>\nabla \cdot \mathbf{E} = \frac {\rho} {\varepsilon_0}</math>,  <math>\nabla \times \mathbf{B} = \mu_0\mathbf{J} + \mu_0 \varepsilon_0 \frac{\partial \mathbf{E}} {\partial t}\ </math>)<br>  <br>
 
 
*  broken [http://resources.aims.ac.za/archive/2009/solomon.pdf Maxwell's Equations in Terms of Dierential Forms]<br>
 
*  broken [http://resources.aims.ac.za/archive/2009/solomon.pdf Maxwell's Equations in Terms of Dierential Forms]<br>
 
* [http://www22.pair.com/csdc/pd2/pd2fre21.htm Maxwell Theory and Differential Forms]<br>
 
* [http://www22.pair.com/csdc/pd2/pd2fre21.htm Maxwell Theory and Differential Forms]<br>

2012년 6월 12일 (화) 19:00 판

Lorentz force
  • almost all forces in mechanics are conservative forces, those that are functions only of positions, and certainly not functions of velocities
  • Lorentz force is a rare example of velocity dependent force

 

 

polarization of light
  • has two possibilites
    • what does this mean?

 

 

 

 

 

 

Lagrangian formulation
  • Lagrangian for a charged particle in an electromagnetic field
    \(L=T-V\)
    \(L(q,\dot{q})=m||\dot{q}||-e\phi+eA_{i}\dot{q}^{i}\)
  • action
    \(S=-\frac{1}{4}\int F^{\alpha\beta}F_{\alpha\beta}\,d^{4}x\)
  • Euler-Lagrange equations
    \(p_{i}=\frac{\partial{L}}{\partial{\dot{q}^{i}}}=m\frac{\dot{q}_{i}}{||\dot{q}_{i}||}+eA_{i}=mv_{i}+eA_{i}\)
    \(F_{i}=\frac{\partial{L}}{\partial{{q}^{i}}}=\frac{\partial}{\partial{{q}^{i}}}(eA_{j}\dot{q}^{j})=e\frac{\partial{A_{j}}}{\partial{q}^{i}}\dot{q}^{j}}}\)
  • equation of motion
    \(\dot{p}=F\) Therefore we get
    \(m\frac{dv_{i}}{dt}=eF_{ij}\dot{q}^{j}\). This is what we call the Lorentz force law.
  • force on a particle is same as \(e\mathbf{E}+e\mathbf{v}\times \mathbf{B}\)

 

 

Hamiltonian formulation
  • total energy of a charge particle in an electromagnetic field
    \(E=\frac{1}{2m}(p_j-eA_{j})(p_j-eA_j)+q\phi\)
  • replace the momentum with the canonical momentum
    • similar to covariant derivative

 

 

force on a particle
  • force on a particle is same as \(e\mathbf{E}+e\mathbf{v}\times \mathbf{B}\)

 

 

 

gauge transformation
  • For any scalar field \(\Lambda(x,y,z,t)\), the following transformation does not change any physical quantity
    \(\mathbf{A} \to \mathbf{A} +\del \Lambda\)
    \(\phi\to \phi-\frac{\partial\Lambda}{\partial t}\)
  • unchanged quantities
    \(\mathbf{B}=\nabla \times \mathbf{A}\)
    \(\mathbf{E}=-\frac{\partial\mathbf{A}}{\partial t} - \nabla \phi \)
  • the electromagnetic potential is a connection on a U(1)-bundle on spacetime whose curvature is the electromagnetic field
  • the electromagnetism is a gauge field theory with structure group U(1)

 

 

 

 

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ELECTROMAGNETIC THEORY AND COMPUTATION