"Bailey pair and lemma"의 두 판 사이의 차이

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<h5 style="margin: 0px; line-height: 2em;">examples of Bailey pair</h5>
 
 
* [[Slater list|Slater's list]]<br>
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
*  If we apply Bailey lemma to the above conjugate pair, we get<br>  <br>
 
 
 
 
 
 
 
 
 
<h5 style="margin: 0px; line-height: 2em;">examples</h5>
 
<h5 style="margin: 0px; line-height: 2em;">examples</h5>
  
 
*  Conjugate Bailey pair (<math>x=q,y\to\infty, z\to\infty</math>)<br><math>\delta_n=q^{n^2}</math><br><math>\gamma_n=\frac{q^{n^2}}{(q)_{\infty}}</math><br>
 
*  Conjugate Bailey pair (<math>x=q,y\to\infty, z\to\infty</math>)<br><math>\delta_n=q^{n^2}</math><br><math>\gamma_n=\frac{q^{n^2}}{(q)_{\infty}}</math><br>
* Bailey pair<br><math>\alpha_{n}=(-1)^{n}q^{\frac{3}{2}n^2}(q^{\frac{1}{2}n}+q^{-\frac{1}{2}n})</math><br><math>\beta_n=\frac{1}{(q)_{n}}</math><br>
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*  we get the Rogers-Ramanujan identity([[5974537|Slater 18]])<br><math>\sum_{n=0}^{\infty}\frac{q^{n^2}}{ (q)_{n}}=\frac{(q^{3};q^{5})_{\infty}(q^{2};q^{5})_{\infty}(q^{5};q^{5})_{\infty}}{(q)_{\infty}}=\frac{1}{(q^{1};q^{5})_{\infty}(q^{4};q^{5})_{\infty}}</math><br>
 
*  we get the Rogers-Ramanujan identity([[5974537|Slater 18]])<br><math>\sum_{n=0}^{\infty}\frac{q^{n^2}}{ (q)_{n}}=\frac{(q^{3};q^{5})_{\infty}(q^{2};q^{5})_{\infty}(q^{5};q^{5})_{\infty}}{(q)_{\infty}}=\frac{1}{(q^{1};q^{5})_{\infty}(q^{4};q^{5})_{\infty}}</math><br>
  
34번째 줄: 12번째 줄:
  
 
* [[6080259|Bailey chain]]<br>
 
* [[6080259|Bailey chain]]<br>
 
 
 
 
 
 
 
<h5 style="background-position: 0px 100%; font-size: 1.16em; margin: 0px; color: rgb(34, 61, 103); line-height: 3.42em; font-family: 'malgun gothic',dotum,gulim,sans-serif;">history</h5>
 
 
* http://www.google.com/search?hl=en&tbs=tl:1&q=
 
  
 
 
 
 

2011년 11월 12일 (토) 06:54 판

examples
  • Conjugate Bailey pair (\(x=q,y\to\infty, z\to\infty\))
    \(\delta_n=q^{n^2}\)
    \(\gamma_n=\frac{q^{n^2}}{(q)_{\infty}}\)
  •  
  • we get the Rogers-Ramanujan identity(Slater 18)
    \(\sum_{n=0}^{\infty}\frac{q^{n^2}}{ (q)_{n}}=\frac{(q^{3};q^{5})_{\infty}(q^{2};q^{5})_{\infty}(q^{5};q^{5})_{\infty}}{(q)_{\infty}}=\frac{1}{(q^{1};q^{5})_{\infty}(q^{4};q^{5})_{\infty}}\)

 

 

Bailey chain

 

 

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