3rd order mock theta functions

수학노트
imported>Pythagoras0님의 2012년 10월 28일 (일) 15:20 판 (찾아 바꾸기 – “</h5>” 문자열을 “==” 문자열로)
둘러보기로 가기 검색하러 가기
introduction==        

shadow

  • \(\Theta(24z)=q-5q^25+7q^{49}-11q^{121}+13q^{169}-\cdots\)
  • \(M_f(z)=q^{-1}f(q^24)+\frac{i}{\sqrt{3}}\int_{}^{}\frac{\Theta(24z)}{}dz\)

 

 

\(f(q) = \sum_{n\ge 0} {q^{n^2}\over (-q;q)_n^2} =1+\sum_{n\ge 1} \frac{q^{n^2}}{(1+q)^2(1+q^2)^2\cdots{(1+q^{n})^2}}={2\over \prod_{n>0}(1-q^n)}\sum_{n\in Z}{(-1)^nq^{3n^2/2+n/2}\over 1+q^n}\)

weight k=1/2, harmonic weak Maass form under \(\Gamma(2)\)

\(h_3(\tau)=q^{-1/24}f(q)+R_3(q)\)

\(R_3(\tau)=\sum_{n\equiv 1\pmod 6}\operatorname{sgn}(n)\beta_{1/2}(n^2y/6)q^{-n^2/24}\) where \(\displaystyle \beta(t) = \int_t^\infty u^{-1/2} e^{-\pi u} \,du=2\int_{\sqrt{x}}^{\infty} e^{-\pi t^2}\,dt\)

\(R_3(\tau)=(i/2)^{k-1} \int_{-\overline\tau}^{i\infty} (z+\tau)^{-k}\overline{g(-\overline z)}\,dz\)

shadow = weight 3/2 theta function

\(g_3(z)=\sum_{n\equiv 1\pmod 6}nq^{n^2/24}\)

 

 

articles

 

 

history==    
related items==    
encyclopedia==    
books==   4909919    
articles==      
question and answers(Math Overflow)==    
blogs==    
experts on the field==    
links==