Quantum dilogarithm

수학노트
http://bomber0.myid.net/ (토론)님의 2010년 5월 19일 (수) 06:38 판
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introduction

 

 

quantum plane
  • noncommutative geometry
  • \(uv=qvu\)

 

 

quantum dilogarithm

\(\Psi(z)=\prod_{n=0}^{\infty}(1-zq^n)=\sum_{n\geq 0}\frac{(-1)^nq^{n(n-1)/2}}{(1-q)(1-q^2)\cdots(1-q^n)} z^n\)

\(\Psi(z)=\exp(\frac{\operatorname{Li}_{2,q}(z)}{q-1})\)

 

\(\operatorname{Li}_{2,q}(z) = -\int_0^z{{\ln (1-t)}\over t} d_{q}t \)

 

\(\operatorname{Li}_2(z) = -\int_0^z{{\ln (1-t)}\over t} dt \)

 

 

 

정의
  • \(0<q<1\)에 대하여 다음과 같이 정의
    \(\int_0^a f(x) d_q x = a(1-q)\sum_{k=0}^{\infty}q^k f(aq^k )\)
    \(\int_0^{\infty} f(x) d_q x =(1-q)\sum_{k=-\infty}^{\infty}q^k f(aq^k )\)
  • \(q\to 1\) 이면, \(\int_0^a f(x) d_q x \to \int_0^a f(x) dx \)

 

 

 

 

 

asymptotics

 

  • \(q=e^{-t}\) and as the t goes 0 (i.e. as q goes to 1)

\(\sum_{n=0}^{\infty}\frac{q^{\frac{A}{2}n^2+cn}}{(q)_n}\sim\exp(\frac{C}{t})\)

where C= sum of Rogers dilogarithms

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