Motive
http://bomber0.myid.net/ (토론)님의 2010년 12월 3일 (금) 08:17 판
geometry roughly= cohomology
examples
circle S^1
Betti cohomolgy (singular cohomology)
H^0(S^1,Z)=Z
H^1(S^1,Z)=Z
\mathbb{G}_m = \mathbb{C}^{x} = \mathbb{C}/{0} same homotopy class as S^1
Betti cohomology is same
H^0(\mathbb{G}_m,Z)=Z
H^1(\mathbb{G}_m,Z)=Z , this is dual to H_1(\mathbb{G}_m,Z)
de Rham cohomology
H^0_{dR}(\mathbb{G}_m)=\mathbb{C}
H^1_{dR}(\mathbb{G}_m)=\mathbb{C}