리대수 sl(4,C)의 유한차원 표현론
개요
- 복소수체 위의 15차원 리대수 <math>\mathfrak{g}=\mathfrak{sl}(4,\mathbb{C})</math>
- <math>\mathfrak{g}=\{X\in \mathfrak{gl}(4,\mathbb{C})|\operatorname{Tr}(X)=0 \}</math>
- <math>A_3</math> 타입의 단순 리대수
리대수 <math>\mathfrak{sl}(4,\mathbb{C})</math>
- 기저
- <math>
\begin{array}{|rcl|} \hline h_1 & = & \left( \begin{array}{cccc} 1 & 0 & 0 & 0 \\ 0 & -1 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
h_2 & = & \left(
\begin{array}{cccc} 0 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & -1 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
h_3 & = & \left(
\begin{array}{cccc} 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & -1 \end{array} \right) \\ \hline
e_1 & = & \left(
\begin{array}{cccc} 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
e_2 & = & \left(
\begin{array}{cccc} 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
e_3 & = & \left(
\begin{array}{cccc} 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
e_4 & = & \left(
\begin{array}{cccc} 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
e_5 & = & \left(
\begin{array}{cccc} 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline
e_6 & = & \left(
\begin{array}{cccc} 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{array} \right) \\ \hline f_i & = & e_i^t,\quad 1\leq i\leq 6 \\ \hline \end{array} </math>
- <math>A_3</math> 카르탄 행렬
- <math>A=\left(
\begin{array}{ccc} 2 & -1 & 0 \\ -1 & 2 & -1 \\ 0 & -1 & 2 \end{array} \right)</math>
- <math>A_3</math> 루트 시스템
- <math>\Phi=\left\{
\alpha _1,\alpha _2,\alpha _3,\alpha _1+\alpha _2,\alpha _2+\alpha _3,\alpha _1+\alpha _2+\alpha _3,\\ -\alpha _1,-\alpha _2,-\alpha _3,-\alpha _1-\alpha _2,-\alpha _2-\alpha _3,-\alpha _1-\alpha _2-\alpha _3 \right \}</math>
- 바일군
- <math>\{s[],s[1],s[2],s[3],s[1,2],s[1,3],s[2,1],s[2,3],s[3,2],\\
s[1,2,1],s[1,2,3],s[1,3,2],s[2,1,3],s[2,3,2],s[3,2,1],\\ s[1,2,1,3],s[1,2,3,2],s[1,3,2,1],s[2,1,3,2],s[2,3,2,1],s[1,2,1,3,2],s[1,2,3,2,1],s[2,1,3,2,1],s[1,2,1,3,2,1]\} </math>
- <math>A_3</math>의 루트 시스템을 <math>\mathbb{R}^4</math>안에서 다음과 같이 얻을 수 있다
- <math>\alpha_1=(1,-1,0,0)</math>
- <math>\alpha_2=(0,1,-1,0)</math>
- <math>\alpha_3=(0,0,1,-1)</math>
- fundamental weights
- <math>\omega_1=(3/4, -(1/4), -(1/4), -(1/4))</math>
- <math>\omega_2=(1/2, 1/2, -(1/2), -(1/2))</math>
- <math>\omega_3=(1/4, 1/4, 1/4, -(3/4))</math>
- 바일 벡터 <math>\rho=(3/2, 1/2, -(1/2), -(3/2))</math>
유한차원 기약 표현의 분류
- 유한차원 기약 표현 <math>V</math>에 대하여, 적당한 dominant weight <math>\omega=a\omega_1+b\omega_2+c\omega_3,\quad a,b,c\in \mathbb{Z}_{\geq 0}</math>가 존재하여, <math>V\cong L(\omega)</math>가 성립
- 바일 차원 공식(Weyl dimension formula)을 이용하면, 다음을 얻는다
- <math>
\dim L(a\omega_1+b\omega_2+c\omega_3)=\frac{1}{12} (a+1) (b+1) (c+1) (a+b+2) (b+c+2) (a+b+c+3) </math>
기약표현의 예
- 표현 <math>V=L(\lambda)</math>의 지표를 다음과 같이 정의
- <math>
\chi_{\lambda}=\sum_{\lambda' \in P} (\dim{V_{\lambda'}})e^{\lambda'} </math>
- <math>x_1=e^{\omega_1}, x_2=e^{\omega_2},x_3=e^{\omega_3}</math>로 두면, <math>\chi_{\lambda}</math>는 <math>\mathbb{Z}[x_1^{\pm},x_2^{\pm},x_3^{\pm}]</math>의 원소가 된다
- 바일 지표 공식 (Weyl character formula) 항목 참조
예1
- fundamental 표현, highest weight은 <math>\omega_1</math>
- 4차원 표현
- 지표
- <math>
\chi_{\omega_1}=x_1+\frac{x_2}{x_1}+\frac{1}{x_3}+\frac{x_3}{x_2} </math>
- weight diagram
예2
- adjoint 표현, highest weight은 <math>\omega_1+\omega_3</math>
- 15차원 표현
- 지표
- <math>
\chi_{\omega_1+\omega_3}=3+\frac{x_1^2}{x_2}+\frac{x_2}{x_1^2}+\frac{x_2}{x_3^2}+\frac{1}{x_1 x_3}+\frac{x_1}{x_2 x_3}+\frac{x_1 x_2}{x_3}+\frac{x_2^2}{x_1 x_3}+x_1 x_3+\frac{x_1 x_3}{x_2^2}+\frac{x_3}{x_1 x_2}+\frac{x_2 x_3}{x_1}+\frac{x_3^2}{x_2} </math>
- weight diagram
예3
- highest weight <math>\omega_1+\omega_2+\omega_3</math>
- 64차원 표현
- weight diagram
관련된 항목들



